Final answer:
On Bhavya's home planet, the range of the Jodgraball is approximately 34.2 meters.
Step-by-step explanation:
To find the range of the Jodgraball on Bhavya's home planet, we need to consider the horizontal and vertical components of its motion. The horizontal component of the initial velocity is 25.0 m/s * cos(40°), which is approximately 19.10 m/s. The time of flight can be found using the equation t = 2 * (vertical component / g), where g is the acceleration due to gravity. The vertical component of the initial velocity is 25.0 m/s * sin(40°), which is approximately 16.09 m/s. Plugging in these values, we find that the time of flight is approximately 1.789 seconds. Finally, to find the range, we multiply the horizontal component of the initial velocity by the time of flight: 19.10 m/s * 1.789 s = 34.1669 m ≈ 34.2 meters.