Question

A bowl contains 500cm ^ 3 of water at a temperature of 5 * C The bowl of water is placed in a freezer for several hours. When the bowl is removed from the freezer, it contains ice at a temperature of -18.0°C. The density of water is 1000kg / (m ^ 3) (1) Calculate the mass of water in the bowl when it is placed in the freezer.​

Answer 1

To find the mass of the water in the bowl, convert the volume to cubic meters and use the density of water to calculate the mass, which is 0.5 kg.

Step-by-step explanation:

To calculate the mass of water in the bowl when it is placed in the freezer, we need to know the density of water and the volume of water in the bowl.

The density of water is given as 1000 kg/(m^3) and the volume of water in the bowl is given as 500 cm^3. First, we need to convert the volume from cm^3 to m^3.

Since 1 m^3 is equal to 1000000 cm^3, the volume of water in the bowl is 500 cm^3 * (1 m^3/1000000 cm^3) = 0.0005 m^3.

Now we can calculate the mass of water using the formula: mass = density * volume. So, mass = 1000 kg/(m^3) * 0.0005 m^3 = 0.5 kg.

Therefore, the mass of water in the bowl when it is placed in the freezer is 0.5 kg.