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A sample of 2.21 grams of Z is dissolved into 500 grams of water which is in a styrofoam coffee cup. The temperature is monitored and is found to drop from 23.512°C to 23.269°C. What is ∆Hsolution for substance Z? Assume no heat is lost/gained by the cup itself. The specific heat of water is 4.184 J/g· °C and the molecular weight of Z is 148 g/mol.

Answer in units of kJ/mol of Z.

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Final answer:

To find the solution for substance Z, we calculate the heat absorbed by the water when Z dissolves, convert it to joules per mole using the molar mass of Z, and then to kilojoules. The ΔHsolution for Z is -34.052 kJ/mol.

Step-by-step explanation:

The question asks to calculate the ΔHsolution for substance Z when a sample of 2.21 grams of Z is dissolved in 500 grams of water, resulting in a temperature change from 23.512°C to 23.269°C. Assuming no heat is lost or gained by the cup itself and using the specific heat of water (4.184 J/g°C), first, we find the amount of heat (q) absorbed or released by the solution using the formula:

q = mass of water × specific heat of water × ΔT

where ΔT is the change in temperature. We then calculate ΔHsolution per mole of Z by using the molar mass of Z (148 g/mol).

The heat q absorbed by the water is:

q = 500 g × 4.184 J/g°C × (23.269°C - 23.512°C)

q = 500 g × 4.184 J/g°C × (-0.243°C)

q = -508.268 J

This value is negative because the temperature decreased, indicating that the solution absorbed heat. To find the heat per mole of Z, we convert the mass of Z (2.21 g) to moles:

moles of Z = 2.21 g ÷ 148 g/mol = 0.0149324 mol

Next, we calculate ΔHsolution:

ΔHsolution = q / moles of Z = -508.268 J / 0.0149324 mol

ΔHsolution = -34052.269 J/mol

The answer needs to be in kilojoules per mole:

ΔHsolution = -34.052 kJ/mol

The ΔHsolution for substance Z is -34.052 kJ/mol, indicating an exothermic dissolution process.

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