Question

a toy car is given an initial velocity of 5.0m/s and comes to a complete stop in 12m.Assuming constant acceleration , how long did it take the car to come to a sop?

Answer 1

The car took approximately 4.81 seconds to come to a complete stop.

Step-by-step explanation:

To find the time it took for the car to come to a stop, we can use the equation:

v^2 = v0^2 + 2aΔx

Where:

• v is the final velocity (0 m/s, since the car came to a stop)
• v0 is the initial velocity (5.0 m/s)
• a is the acceleration (unknown)
• Δx is the displacement (12 m)

Plugging in the known values into the equation, we have:

0^2 = (5.0)^2 + 2a(12)

25 = 24a

a = 25/24 = 1.04 m/s^2

Now, we can use the equation:

v = v0 + at

Plugging in the known values, we have:

0 = 5.0 + (1.04)t

t = -5.0/1.04 = -4.81 s

Since time cannot be negative, we discard the negative value.

Therefore, it took the car approximately 4.81 seconds to come to a complete stop.