Final answer:
The energy required to heat 150g of water from 25.0°C to 75.0°C is 31,350 joules, using the specific heat capacity of water and the formula Q = m × c × ΔT.
Step-by-step explanation:
To calculate the amount of energy required to heat 150g of water from 25.0°C to 75.0°C, we use the formula: Q = m × c × ΔT, where:
- Q is the heat energy in joules,
- m is the mass of the water in grams,
- c is the specific heat capacity in J/g°C,
- ΔT is the change in temperature in degrees Celsius.
Plugging in the given values:
- m = 150g,
- c = 4.18 J/g°C,
- ΔT = (75.0 - 25.0)°C = 50.0°C.
The calculation becomes:
Q = 150g × 4.18 J/g°C × 50.0°C = 31350 J
So, the energy required to heat the water by 50°C is 31,350 joules.