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If a car travels around the DC beltway, it travels

100.0 km. When a car completes one circle around
the DC beltway.
a. what distance does it travel?

1 Answer

4 votes

Final answer:

If a car travels around the DC beltway, it covers a distance of 100.0 km. A rabbit running at 10 km/h has a speed of approximately 2.78 m/s. The speed limit of 100 km/h is equivalent to about 62.14 mph. A car with 0.260 m radius tires will make approximately 49,087,385 revolutions when traveling 80,000 km.

Step-by-step explanation:

If a car travels around the DC beltway, it travels 100.0 km. When a car completes one circle around the DC beltway, the distance it travels is exactly the length of the beltway, which is 100.0 km.

b. To determine how long it will take a car to travel 100 m, we need to know the speed of the car. Without this information, we cannot calculate the time required.

c. If the rabbit is running at 10 km per hour, its speed in meters per second (m/s) can be calculated using unit conversion: 1 km/h is equal to ≈ 0.278 m/s. Therefore, a rabbit running at 10 km/h is running at approximately 2.78 m/s (since 10 × 0.278 = 2.78).

14. The speed limit on some interstate highways of 100 km/h is equivalent to approximately 62.14 miles per hour, considering that 1 mile is about 1.609 km (100 ÷ 1.609 ≈ 62.14).

3. An automobile with 0.260 m radius tires that travels 80,000 km before wearing out will make a number of tire revolutions determined by dividing the total distance travelled by the circumference of the tires. The circumference of one tire is 2π × radius = 2π × 0.260 m. The total distance traveled in meters is 80,000 km × 1,000 m/km = 80,000,000 m. Hence, the number of revolutions is 80,000,000 ÷ (2π × 0.260) ≈ 49,087,385 revolutions.

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