Final answer:
The question involves writing balanced chemical reactions for the complete combustion of methane and ethane, creating a diagram of the process, deriving stoichiometric equations for theoretical air estimation, and discussing how excess air requirements change with incomplete combustion.
Step-by-step explanation:
The given information describes the complete combustion of a natural gas mixture containing methane (CH4) and ethane (C2H6).
Part A: Balanced Chemical Reactions
The balanced chemical reactions for combustion of methane and ethane are as follows:
For methane (CH4):
CH4 + 2O2 → CO2 + 2H2O
For ethane (C2H6):
2C2H6 + 7O2 → 4CO2 + 6H2O
Part B: Diagram of Combustion Process
The diagram should show inflow of 95 moles of methane and 5 moles of ethane, and outflow of the various products with the specific mole percentages given.
Part C: Stoichiometric Equations
The stoichiometric equations will relate the moles of methane and ethane to the moles of oxygen needed for complete combustion.
Part D: Excess Air
If only 75% of the natural gas is burned, the requirement for excess air would decrease proportionately to the amount of fuel not combusted, as less oxygen is necessary for incomplete combustion.