Question

theorem: for any real number in a proof by cases of the theorem, there are two cases. one of the cases is that . what is the other case?

Answer 1

In a proof by cases of a theorem, there are two cases when considering a real number: one when it is positive and the other when it is negative.

Step-by-step explanation:

In a proof by cases of a theorem, when considering a real number, there are two cases. One case is when the number is positive, and the other case is when the number is negative.

For example, let's say we have the theorem 'If x is a real number, then x^2 > 0'. The two cases would be:

1. When x > 0, x^2 > 0.
2. When x < 0, x^2 > 0.