Question

The total impedance of a series circuit is the sum of the impedances of all parts of the circuit. Suppose that the first part of a circuit has an impedance of 6 - 5j ohms and that the total impedance of the circuit was 12 + 7j ohms. What is the impedance of the remainder of the circuit?

a) 6 + 5j ohms
b) 18 - 12j ohms
c) 6 + 12j ohms
d) 18 - 7j ohms

Answer 1

The impedance of the remainder of the circuit is found by subtracting the impedance of the first part from the total impedance, resulting in 6 + 12j ohms.

Step-by-step explanation:

The total impedance of a series circuit is the sum of the impedances of all components in the circuit. The impedance of the first part of the circuit is given as 6 - 5j ohms, and the total impedance of the circuit is 12 + 7j ohms. To find the impedance of the remainder of the circuit, you subtract the impedance of the first part from the total impedance:

Total Impedance - Impedance of the first part = Impedance of the remainder

(12 + 7j) - (6 - 5j) = 6 + 12j ohms

Therefore, the answer is c) 6 + 12j ohms.