Final answer:
The work done by the electric field in moving a -7.7 μc charge from ground to a point with a potential that is 60 V higher is -462 μJ.
Step-by-step explanation:
The work done by an electric field in moving a charge can be calculated using the formula:
Work = qΔV
where q is the charge and ΔV is the change in electric potential. In this case, the charge is -7.7 μC and the change in potential is 60 V. As the charge is negative, the work done by the electric field will be negative and can be calculated as:
Work = (-7.7 μC) * (60 V) = -462 μJ
Therefore, the electric field does -462 μJ of work in moving the charge from ground to a point with a potential that is 60 V higher.