Final answer:
The electric potential energy of a –3.0 µC charge placed at a point with electric potential of 12 V is –.0036 joules.
Step-by-step explanation:
The electric potential energy (U) of a charge (q) in an electric field with potential (V) is given by the formula U = qV. In this case, the electric potential at the point in space is 12 V, and the charge being placed at that point is –3.0 µC (–.0003 C). To find the electric potential energy, we multiply the charge by the potential:
U = qV = (–3.0 µC)(12 V) = –.0003 C × 12 J/C = –.0036 J
Therefore, the electric potential energy of a –3.0 µC charge placed at that point is –.0036 joules.