Final answer:
The boiling point of water on this faulty temperature scale is 210°C, which is not one of the listed options, hence option D (None of the above) is correct.
Step-by-step explanation:
The question asks us to determine the boiling point of water on a faulty temperature scale. On the conventional Celsius scale, the freezing point of water is at 0°C, and the boiling point is at 100°C. The thermometer in question has a delineation error; it reads -10°C for the freezing point and 60°C for what should actually be 50°C. This implies that for every 10°C increment on the conventional scale, the faulty thermometer reads 20°C. Consequently, for the conventional 100°C boiling point, the increment would be 100°C / 10°C × 20°C = 200°C on the faulty scale. Therefore, the temperature of the boiling point of water on this faulty scale is 10°C (initial incorrect value) + 200°C (calculated increment) = 210°C, which corresponds to option D (None of the above).