Final answer:
The correct application of the addition rule for the given problem is Option A, which states P(A or B) = P(Child ticket) + P(Afternoon) - P(Child ticket and Afternoon). It's important to calculate the probability of each event individually as well as the joint probability to avoid double-counting.
Step-by-step explanation:
To apply the addition rule for the events 'a child ticket is bought for a play' and 'the play is performed in the afternoon,' we will use the given formula: P(A or B) = P(A) + P(B) - P(A and B). In this context, Event A is 'a child ticket is bought' and Event B is 'the play is performed in the afternoon'. To calculate P(A or B), we need to find the probability of Event A, the probability of Event B, and the probability of both events occurring together (Event A and B). Once we have these probabilities, we plug them into the addition rule formula.
By looking at the table (not provided in the question, but usually included in such problems), we would calculate the probability of each individual event by dividing the number of occurrences of the event by the total number of tickets or plays as appropriate. And the probability of both A and B happening, which is a child ticket being bought for an afternoon play, would be found similarly. Then we would subtract the probability of both A and B from the sum of the probabilities of A and B to avoid double-counting the intersection.
The correct application from the options provided would be Option A, which correctly represents the addition rule: P(A or B) = P(Child ticket) + P(Afternoon) - P(Child ticket and Afternoon).