Question

Dee is on a swing in the playground. The chains are 2.5 m long, and the tension in each chain is 350 N when Dee is 75 cm above the lowest point of her swing. Tension is a vector directed along the chain, measured in newtons, abbreviated N .

Part A
What is the magnitude of the horizontal component of the tension at this point in the swing?
Part B
What is the magnitude of the vertical component of the tension at this point in the swing?

Answer 1

To find the magnitudes of the horizontal and vertical components of the tension, we can use trigonometry.

Step-by-step explanation:

To find the magnitudes of the horizontal and vertical components of the tension, we can use trigonometry. We know that the tension in each chain is 350 N and Dee is 75 cm above the lowest point of her swing. Since the chains are 2.5 m long, we can use the sine and cosine functions to find the horizontal and vertical components of the tension.

Part A: The magnitude of the horizontal component of the tension is given by T * cos(angle) = 350 N * cos(75 cm / 2.5 m).

Part B: The magnitude of the vertical component of the tension is given by T * sin(angle) = 350 N * sin(75 cm / 2.5 m).