Question

If the initial temperature of a movable cylinder was 130 degrees Celsius

with a pressure of 1 ATM and an initial volume of 2 Liters, what would
the new volume be if the temperature was lowered to 324 degrees Kelvin
and the pressure was raised to 1.1 ATM?

Answer 1

Answer: The new volume will be 1.5 L

Step-by-step explanation:

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 1 atm

`P_2` = final pressure of gas = 1.1 atm

`V_1` = initial volume of gas = 2 L

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`130^0C=(130+273)K=403K`

`T_2` = final temperature of gas =
`324K`

Now put all the given values in the above equation, we get:

`(1* 2)/(403)=(1.1* V_2)/(324)`

`V_2=1.5L`

The new volume will be 1.5 L