Final answer:
The probability that the second ticket is an odd number given that the first ticket is 2 is 3/5, calculated by considering that one of the '2' tickets has been removed and adjusting the sample space accordingly.
Step-by-step explanation:
To find the probability that the second ticket is an odd number given that the first ticket is 2 from a pool of tickets {1, 1, 1, 2, 2, 2, 3, 3, 4, 4, 5}, we must consider that one of the '2' tickets has been removed after the first draw. Thus, the second draw is from the set {1, 1, 1, 2, 2, 3, 3, 4, 4, 5}. There are six odd tickets remaining: three '1's, two '3's, and one '5'.
The total number of remaining tickets is 10. The probability of drawing an odd ticket is the number of odd tickets (6) over the total number of remaining tickets (10), so P(odd on 2nd draw | 2 on 1st draw) = 6/10, which simplifies to 3/5.
Remember, when calculating conditional probabilities, we adjust the sample space based on the condition given, which in this case is that the first ticket drawn was a '2'.