Final answer:
The work done in moving a charge of 2.5 μC a distance of 22 cm along an equipotential at 10 V is 2.5 × 10-5 J.
Step-by-step explanation:
The work done in moving a charge of 2.5 μC a distance of 22 cm along an equipotential at 10 V can be calculated using the formula:
Specifically, when a charge of 2.5μC moves a distance of 22cm along an equipotential at 10V, since there's no potential difference, the work done, W, is given by W = qΔV, which equals 2.5μC times 0 V. This results in zero joules of work being done.
Work = charge × potential difference
Substituting the given values, we get:
Work = (2.5 × 10-6 C) × (10 V) = 2.5 × 10-5 J
Therefore, the work done is 2.5 × 10-5 J.