Question

What are the first 3 terms of the sequence whose nth term is an = 2^(9n-1)?

A) 9, 18, 36
B) 2, 11, 20
C) 9, 11, 13
D) 2, 18, 162

Answer 1

The first 3 terms of the sequence are 256, 2^17, and 2^26.

Step-by-step explanation:

The nth term of the sequence is given by an = 2^(9n-1). To find the first 3 terms, we substitute n = 1, 2, and 3 into the formula:

1. a1 = 2^(9(1)-1) = 2^(9-1) = 2^8 = 256
2. a2 = 2^(9(2)-1) = 2^(18-1) = 2^17
3. a3 = 2^(9(3)-1) = 2^(27-1) = 2^26

Therefore, the first 3 terms of the sequence are 256, 2^17, and 2^26.