91.7k views
5 votes
Solve the equation: x^3 = 8/27
a. x = 2
b. x = 3
c. x = 4
d. x = 6

1 Answer

1 vote

Final answer:

The quadratic equation x² +0.0211x -0.0211 = 0 can be solved using the quadratic formula. The solutions are approximately x ≈ 0.1021 or x ≈ -0.1232.

Step-by-step explanation:

This quadratic equation can be solved using the quadratic formula.

Given the equation x² +0.0211x -0.0211 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values a = 1, b = 0.0211, and c = -0.0211 into the formula, we get:

x = (-0.0211 ± √((0.0211)² - 4(1)(-0.0211))) / (2(1))

Simplifying further, the solution is:

x = (-0.0211 ± √(0.00044521 + 0.0848)) / 2

Therefore, the solutions to the equation are approximately:

x ≈ 0.1021 or x ≈ -0.1232

User Harry Binswanger
by
7.2k points