Final answer:
To obtain ΔrH° at 500°C and 1 bar for the reaction C₂H₅OH(l) → C₂H₆(g) + 1/2O₂(g), you would need further data such as the standard enthalpy change of formation for each substance involved.
Step-by-step explanation:
To obtain ΔrH° at 500°C and 1 bar for the reaction C₂H₅OH(l) → C₂H₆(g) + 1/2O₂(g), you would need further data such as the standard enthalpy change of formation for each substance involved. The standard enthalpy change of formation, ΔfH°, is the enthalpy change when one mole of a substance is formed from its elements in their standard states.
By subtracting the standard enthalpy change of formation of the reactants from the standard enthalpy change of formation of the products, you can calculate ΔrH°. The equation would be: ΔrH° = (∑nΔfH°products) - (∑nΔfH°reactants), where n represents the stoichiometric coefficients of each substance in the balanced equation.
Therefore, in order to determine ΔrH° at 500°C and 1 bar for the given reaction, you would need the standard enthalpy change of formation values for C₂H₅OH(l), C₂H₆(g), and 1/2O₂(g) at that temperature and pressure.