354,095 views
34 votes
34 votes
Nonlinear Systems of EquationsCreate a system of equations that includes one linear equation and one quadratic equation.Part 1. Show all work in solving your system of equations algebraically.Part 2. Graph your system of equations and show the solution graphically to verify your solution.

User Paul Cager
by
2.7k points

1 Answer

20 votes
20 votes

A Part:

The linear system of equation is can be seen as:

(1) 2.y = 3.x + 2

(2) y = 2.x² - 3.x + 2

A sytem of equations are a given number of equations from which a common solution of the system can be found..

A linear equation is an algebraic equation im which the maximum exponent of the variables is one and the graph of the equation is a straight line which is of the form: y = mx + c.

A maximum value of the exponents of the variable quadratic equation is 2, and the general form of the quadratic equation is ax² + bx + c, where a, b, and c are real numbers.

Therefore, the system of equation that can be created is as follows:

2.y = 3.x + 2

y = 2.x² - 3 + 2

To solve the equation:

Let's divide equation (1) by 2, and equate both values of y to find the common solution.

2y/2 = (3x + 2)/2 = 1.5x + 1

y = 1.5x + 1

Let's equate bothj values of y:

y = 1.5x + 1

y = 2x² - 3 + 2

So,

1.5x + 1 = 2x² - 3 + 2

2x² - 3x - 1.5x + 2 - 1 = 0

2x² - 4.5x + 1 = 0

Using formula method:

x = 4.5 ± √((-4.5² - 4 * 2 * 1))/(2 * 2)

x = 2, or x = 0.25

From which we get:

y = 1.5 × 2 + 1 = 4, or y = 1.5 × 0.25 + 1 = 1.375.

User Vitor Baptista
by
2.5k points