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How do you calculate the number of formula units for 6.82 x 10^-6 mol of lead(II) nitrate?

a) 6.82 x 10^6
b) 6.82 x 10^6 units
c) 6.82 x 10^6 molecules
d) 6.82 x 10^6 formula units

1 Answer

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Final answer:

To find the number of formula units of lead(II) nitrate, you multiply the given moles (6.82 x 10^-6 mol) by Avogadro's number (6.022 x 10^23 units/mol), resulting in 4.1 x 10^18 formula units, which is not listed in the given options.

Step-by-step explanation:

To calculate the number of formula units for 6.82 x 10-6 mol of lead(II) nitrate, we need to use Avogadro's number, which is 6.022 x 1023 particles per mole. This conversion factor helps us determine how many individual formula units are present in a given amount of substance in moles.

We can perform this calculation using the following steps:

  1. Start with the given number of moles of lead(II) nitrate, which is 6.82 x 10-6 mol.
  2. Multiply this number by Avogadro's number (6.022 x 1023 formula units/mol) to find the total number of formula units: 6.82 x 10-6 mol x 6.022 x 1023 formula units/mol.
  3. The moles cancel out, leaving us with the number of formula units, which will be 4.1 x 1018 formula units.

Therefore, the correct answer is 4.1 x 1018 formula units, which is not explicitly given in the options. It seems there might be an error in the provided choices.

User FlowRaja
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