Final answer:
The total number of oxygen atoms involved in the formation of 4H3PO4 from P4O10 and H2O2, assuming a typo in the chemical equation, is 12 oxygen atoms, which are found in the product 4H3PO4.
Step-by-step explanation:
The student has asked about the number of oxygen atoms involved in the formation of 4H3PO4 from the reaction P4O10 + H2O2 --> 4H3PO4. However, the chemical equation provided is not balanced and contains a typo regarding the phosphorus oxide formula. Assuming that the correct balanced chemical reaction is P4O10 + 6H2O > 4H3PO4, the phosphorus oxide P4O10 contains 10 oxygen atoms and water (H2O) contributes an additional 12 oxygen atoms when we account for the 6 water molecules reacting. In total, 10 (from P4O10) + 12 (from 6H2O) equals 22 oxygen atoms before the reaction.
After the reaction, in 4 molecules of H3PO4, there are 4 x 4 = 16 oxygen atoms present in the phosphoric acid. Therefore, the total number of oxygen atoms involved in the formation of 4H3PO4 is the number of oxygen atoms in the phosphoric acid, which is answer option (d) 12 oxygen atoms.