25.0k views
1 vote
Joe and Peter go to the fair on Tuesday. They buy 8 pretzels and 8 nachos and spend no more than $40. On Thursday, they return to the fair and purchase 2 pretzels and 5 nachos and spend no more than $20. Write the inequalities and graph the solution.

a) 8x + 8y ≤ 40; 2x + 5y ≤ 20
b) 8x + 8y ≥ 40; 2x + 5y ≥ 20
c) 8x + 8y < 40; 2x + 5y < 20
d) 8x + 8y > 40; 2x + 5y > 20

User Asani
by
7.8k points

1 Answer

4 votes

Final answer:

The correct answer is a) 8x + 8y ≤ 40; 2x + 5y ≤ 20. To graph the solution, plot the inequalities on a coordinate plane and shade the region that satisfies both inequalities.

Step-by-step explanation:

The correct answer is: a) 8x + 8y ≤ 40; 2x + 5y ≤ 20.

To write the inequalities, we need to determine the maximum amount spent on pretzels and nachos on Tuesday and Thursday. Let x represent the number of pretzels and y represent the number of nachos.

On Tuesday, they spent no more than $40, so 8x (cost of pretzels) + 8y (cost of nachos) ≤ 40.

On Thursday, they spent no more than $20, so 2x (cost of pretzels) + 5y (cost of nachos) ≤ 20.

To graph the solution, we can plot these inequalities on a coordinate plane and shade the region that satisfies both inequalities. The shaded region represents the possible combinations of pretzels and nachos they can buy without exceeding their budget.

User Jarin Udom
by
7.4k points