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Gold has a density of 17.3 g/cm^3. What is the volume of a 285g piece of gold?

a) 15.79 cm^3
b) 16.47 cm^3
c) 17.3 cm^3
d) 18.32 cm^3

1 Answer

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Final answer:

The volume of a 285g piece of gold with a density of 17.3 g/cm³ is calculated using the formula V = m / d, which yields approximately 16.47 cm³.

Step-by-step explanation:

To find the volume of a 285g piece of gold with a density of 17.3 g/cm³, you can use the formula for density, where density (d) = mass (m) / volume (V). Rearranging the formula to solve for volume gives us V = m / d. Plugging in the values we have V = 285g / 17.3 g/cm³. When you calculate this, you get the volume V ≈ 16.47 cm³.

Therefore, the correct answer is: b) 16.47 cm³.

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