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the plates of a parallel-plate capacitor are 3.28 mm apart, and each has an area of 9.92 cm2. each plate carries a charge of magnitude 4.40×10−8 c. the plates are in vacuum.

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Final answer:

This physics question requires calculating various properties of a parallel-plate capacitor based on given dimensions and charge carried by the plates within a vacuum environment.

Step-by-step explanation:

The question asked pertains to the calculation of various parameters of a parallel-plate capacitor within a vacuum, given certain physical characteristics such as the separation distance, area of the plates, and the charge each plate carries. To solve problems like this, one needs to understand the relationship between a capacitor's physical attributes (plate area and separation), the charge it carries, and the resulting electrical properties such as capacitance, electric field, potential difference, and stored energy. These calculations involve using fundamental physics formulas that relate to electrostatics and capacitors.

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