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Graph the parabola g(x) =-(x+2)^2+4

1 Answer

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The graph of the function represented by the equation is attached

How to graph the function represented by the equation

From the question, we have the following parameters that can be used in our computation:

g(x) = -(x + 2)² + 4

The vertex of the above function is

(-2, 4)

The axis of symmetry is the x-coordinate of the vertex

So, we have

x = -2

The y-intercept is when x = 0

So, we have

g(0) = -(0 + 2)² + 4

Evaluate

g(0) = 0

Because the leading coefficient is negative, the function has a maximum vertex

Lastly,

The domain is the set of all real values, and the range is (-∞, 4]

The graph is attached

Graph the parabola g(x) =-(x+2)^2+4-example-1
User Cachapa
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