Question

156 g C12H22O11 (sucrose) is dissolved into 4.0 L of solution. What is the molar concentration of the solution? Report your answer with the correct number of significant figures.

Provide your answer below?

Answer 1

The molar concentration of a sucrose solution made by dissolving 156 g of sucrose in 4.0 L of solution is 0.1139 M, calculated by dividing the number of moles of sucrose by the volume of the solution.

Step-by-step explanation:

To calculate the molar concentration of the solution, you first need to find the number of moles of sucrose dissolved. Using the molar mass of sucrose (C12H22O11), which is 342.297 g/mol, we can calculate the moles of sucrose in 156 g.

Number of moles = Mass of sucrose (g) / Molar mass of sucrose (g/mol) = 156 g / 342.297 g/mol ≈ 0.4556 mol

Now that we have the moles of sucrose, we can find the molar concentration (M) which is moles of sucrose per liter of solution.

Molar concentration = Moles of sucrose / Volume of solution (L) = 0.4556 mol / 4.0 L = 0.1139 M

The molar concentration of the sucrose solution is 0.1139 M, with the correct number of significant figures.