Question

`ln(12/38.6)/-0.1947`

Answer 1

The value is
`ln(0.310880829^(−5.1361068310))`

It looks like you're trying to evaluate the expression
`\((\ln\left((12)/(38.6)\right))/(-0.1947)\)`. Let's break it down step by step:

`\[ (\ln\left((12)/(38.6)\right))/(-0.1947) \]`

First, calculate the natural logarithm of the fraction inside:

`\[ \ln\left((12)/(38.6)\right) \]`

`\[ \ln\left((0.31088)/(1)\right) \]`

Now, compute the natural logarithm:

`\[ \ln(0.31088) \]`

Now, divide this result by \(-0.1947\):

`\[ (\ln(0.31088))/(-0.1947) \]`

Apply the logarithm power identity:

ln(0.310880829 1/-0.1947)

Divide the numbers:

ln(0.310880829 −5.1361068310 )

Therefore the value is
`ln(0.310880829^(−5.1361068310))`