Final answer:
The interplanar spacing for a crystallographic plane with Miller indices (2,3,2) in a cubic system with unit cell edge length a is a/√17.
Step-by-step explanation:
The student asked about finding the distance between adjacent planes in a crystal given the Miller indices of a plane are (2,3,2). In crystallography, the distance between adjacent planes, also known as interplanar spacing, is an important concept.
For a cubic crystal system with unit cell edge length a, the Miller indices (h,k,l) are used to calculate the distance (d) between adjacent crystallographic planes using the formula:
d = a / √(h² + k² + l²)
Plugging in the Miller indices for the given plane (2,3,2), the interplanar spacing is calculated as:
d = a / √(2² + 3² + 2²)
After doing the math:
d = a / √(4 + 9 + 4)
d = a / √17
Therefore, the distance between adjacent planes with Miller indices of (2,3,2) is a / √17, where a is the unit cell edge length.