Question

A 6.0 g ice cube at -30 ∘C is in a rigid, sealed container from which all the air has been evacuated. Steam has CV = 1500 J/kg⋅K and CP = 1960 J/kg⋅K.

How much heat is required to change this ice cube into steam at 240 ∘C ? Q=??? in J

Answer 1

To calculate the heat required to change the ice cube into steam at 240°C, we need to consider the different phase changes and temperature changes involved. By using specific heat capacities and heat of fusion/vaporization values, we can calculate the total heat required.

Step-by-step explanation:

To calculate the heat required to change the ice cube into steam at 240°C, we need to consider the different phase changes and temperature changes involved. First, we need to heat the ice from -30°C to its melting point at 0°C using the formula Q = mcΔT, where m is the mass of the ice, c is the specific heat capacity of ice, and ΔT is the change in temperature. Then, we need to calculate the heat required to melt the ice using the formula Q = mHfus, where Hfus is the heat of fusion. Next, we need to heat the resulting water from its melting point to 100°C using the formula Q = mcΔT. After reaching 100°C, we need to calculate the heat required to convert the water to steam using the formula Q = mHvap, where Hvap is the heat of vaporization. Finally, we need to heat the steam from 100°C to 240°C using the formula Q = mcΔT. By adding up all these heat values, we can determine the total heat required.