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30 cm long wrench is being used to try to turn a nut. there are three forces acting on the handle of the wrench.A 5N force is applied at right angles to the end of the wrench handle (farthest from the nut). another 5n force is applied at right angles to the center of the wrench handle. a 10 n force is applied parlallel to the end of the wrench handle. what is the torque on the nut due to each force?

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Final answer:

To calculate the torque, you multiply the force exerted by the distance from the pivot point. The torques produced by the 5N forces are 1.5 N·m at the end, and 0.75 N·m at the center. The 10N parallel force produces no torque.

Step-by-step explanation:

The question is asking to calculate the torque produced by three different forces acting on a wrench. Torque is the product of the force applied and the distance from the pivot point at which the force is applied, and it is maximized when the force is applied perpendicularly to the lever arm. The SI unit of torque is newton meters (N·m).

The first force of 5N is applied perpendicularly at the end of the wrench (30 cm from the nut). The torque (τ) can be calculated using the formula: τ = F × r, where F is the force and r is the distance from the pivot point (nut). Therefore, the torque from this force is τ = 5N × 0.30m = 1.5 N·m.

The second force of 5N is applied perpendicularly at the center of the wrench (15 cm from the nut). The torque from this force is τ = 5N × 0.15m = 0.75 N·m.

The third force of 10N is applied parallel to the wrench handle, and since torque requires a perpendicular distance to calculate, a parallel force will not produce torque on the nut, so the torque is 0 N·m.

User Jeanet
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