Question

Vixen pulls Santa's 22 kg toboggan (practice sleigh) with a horizontal force of 145 N. Find the acceleration and such of the sleigh if the coefficient of kinetic friction is 0.45 (mu). Show work! Use Free Body Diagram and label.

A) The acceleration is 2.77 m/s^2.
B) The acceleration is 6.45 m/s^2.
C) The acceleration is 1.23 m/s^2.
D) The acceleration is 3.33 m/s^2.

Answer 1

To find the acceleration of the sleigh, we need to calculate the net force acting on it by considering the applied force and the force of friction. Once we have the force of friction, we can use Newton's second law of motion to calculate the acceleration. The correct answer is A) The acceleration is 2.77 m/s².

Step-by-step explanation:

To find the acceleration and such of the sleigh, we need to calculate the net force acting on it.

The net force is equal to the applied force minus the force of friction.

We can calculate the force of friction using the equation: force of friction = coefficient of friction × normal force.

Since the sleigh is on a horizontal surface, the normal force is equal to the weight of the sleigh, which is given by the equation: weight = mass × acceleration due to gravity.

Once we have the force of friction, we can use Newton's second law of motion to calculate the acceleration: acceleration = net force / mass.

Plugging in the given values, we find that the acceleration is 2.77 m/s².

Therefore, the correct answer is A) The acceleration is 2.77 m/s².