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Calculate the heat in joules required to melt 26 grams of ice. Given that heat of fusion of water = 334 J/g.

A) 434 J
B) 13,580 J
C) 8,684 J
D) 14 J

1 Answer

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Final answer:

To melt 26 grams of ice, the heat required is calculated by multiplying the mass of the ice by the heat of fusion of water (334 J/g). The resulting calculation is 26 g multiplied by 334 J/g, which equals 8684 J.

Step-by-step explanation:

To calculate the heat in joules required to melt 26 grams of ice, we can use the heat of fusion of ice which is given as 334 J/g. The heat of fusion is the amount of energy required to change a solid into a liquid at its melting point without changing its temperature.

The formula used to calculate the energy required to melt the ice is:

Q = m × Lf

where:
Q = heat required (in joules),
m = mass of ice (in grams),
Lf = heat of fusion (in joules per gram).

We can substitute the given values into the equation:

Q = 26 g × 334 J/g

Q = 8684 J

Therefore, the heat required to melt 26 grams of ice is 8684 J.

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