Question

a certain 10 v power supply cannot provide more than 7 a of current. how many 80 ω resistors could be connected in parallel across its output terminals before it would reach its current limit?

Answer 1

To calculate the number of 80-Ohm resistors that can be connected in parallel across a 10V power supply before reaching its current limit, we can use Ohm's Law to find the current provided by the power supply. By dividing the total resistance of the resistors by the individual resistance of each resistor, we can determine the number of resistors that can be connected in parallel.

Step-by-step explanation:

To determine the number of 80-Ohm resistors that can be connected in parallel across a 10V power supply before reaching its current limit, we need to find the current provided by the power supply.

Using Ohm's Law, we can calculate the current using the formula I = V/R, where I is the current, V is the voltage, and R is the resistance. In this case, since the power supply cannot provide more than 7A of current, we have:

I = 7A

V = 10V

Using the formula, we can rearrange it to solve for R:

R = V/I = 10V / 7A = 10/7 Ohms

Now, we can determine the number of resistors that can be connected in parallel by dividing the total resistance of the resistors by the individual resistance of each resistor:

Number of Resistors = Total Resistance / Individual Resistance = (10/7) Ohms / 80 Ohms = 10/560 = 1/56

Therefore, the power supply can only support connecting 1/56 of an 80-Ohm resistor in parallel before reaching its current limit.