Final answer:
The magnitude of the force experienced by a -2.7μC charge in an electric field with a strength of 7.20 × 10^5 N/C would be 1.944 N.
Step-by-step explanation:
To calculate the magnitude of the force experienced by a -2.7μC charge in an electric field (E), you simply multiply the charge value (q) by the strength of the electric field. The given electric field strength (E) is not provided for the new charge of -2.7μC in the question. However, if it is the same as the field strength provided for the -0.250μC charge, which is 7.20 × 105 N/C, then we would use the formula:
F = qE
Substituting the known values:
F = (-2.7 × 10-6 C)(7.20 × 105 N/C)
This yields a force:
F = -1.944 N
The negative sign indicates the direction of the force is opposite to the direction of the electric field, but since the question asks for the magnitude, we take the absolute value:
|F| = 1.944 N