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An electric dipole is formed from ± 2.0 nC point charges spaced 2.0 mm apart. The dipole is centered at the origin, oriented along the y-axis.

a. What is the electric field strength at point (x, y) = (25 mm, 0 cm)?
b. What is the electric field strength at point (x, y) = (0 cm, 25 mm)?

User Sonjz
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Final answer:

The electric field strength of a dipole at a given point is computed using the principle of superposition for point charges and special formulas for points along the axis or perpendicular bisector of the dipole.

Step-by-step explanation:

The question involves calculating the electric field strength created by an electric dipole at specific points in space. The dipole is formed by two point charges, +2.0 nC and -2.0 nC, separated by 2.0 mm along the y-axis and centered at the origin.

Electric Field at (25 mm, 0 cm)

The electric field at a point due to a single charge is given by E = kQ/r², where k is Coulomb's constant, Q is the charge, and r is the distance from the charge to the point of interest. The total electric field at point (25 mm, 0) due to the dipole is the vector sum of the electric fields due to each charge.

Electric Field at (0 cm, 25 mm)

At this point, we are along the axis of the dipole, and the electric field is directed along the axis of the dipole, getting weaker with distance. We can find the electric field on the axis of a dipole using the formula E = k(2qd)/r³, where d is the separation between the charges and r is the distance from the center of the dipole to the point.

User Birdoftheday
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