Final answer:
The potential difference between the plates is 35,250 V. The potential 1.00 cm from the plate with the lowest potential and 3.00 cm from the other plate is 7,500 V.
Step-by-step explanation:
The potential difference between the plates can be calculated using the formula: V = Ed. where V is the potential difference, E is the electric field strength, and d is the distance between the plates. In this case, the electric field strength is given as 7.50 x 104 V/m and the distance between the plates is 0.47 cm. Substituting these values into the formula, we get: V = (7.50 x 104 V/m) x (0.47 cm). Therefore, the potential difference between the plates is 35,250 V. To find the potential 1.00 cm from the plate with the lowest potential and 3.00 cm from the other plate, we can use the same formula with a different distance value. The distance in this case is 1.00 cm. Substituting the values into the formula, we get: V = (7.50 x 104 V/m) x (1.00 cm). Therefore, the potential at this point is 7,500 V.