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If the voltage difference across bulb #1 in a two-bulb series circuit equals 1.75 V and the current through bulb #1 equals 0.245 A what is the current through bulb #2?

User Shape
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1 Answer

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Final answer:

In a series circuit, the voltage and resistance are constant for all bulbs. Using Ohm's law, we can calculate the resistance of bulb #1 and use it to find the current through bulb #2.

Step-by-step explanation:

In a series circuit, the voltage across each bulb is the same. Since the voltage difference across bulb #1 is 1.75 V, the voltage across bulb #2 is also 1.75 V.

Using Ohm's law (V = I * R), we can calculate the resistance of bulb #1.

1.75 = 0.245 * R => R = 1.75 / 0.245 = 7.14 Ω

Now, to find the current through bulb #2, we can use Ohm's law again.

1.75 = I * 7.14 => I = 1.75 / 7.14 = 0.245 A

Therefore, the current through bulb #2 is also 0.245 A.

User Dothem
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