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What is the y-intercept (b) of the line passing through (-2, 8) and PERPENDICULAR to y = 2x + 52?

a) -44
b) 44
c) -48
d) 48

1 Answer

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Final answer:

The y-intercept (b) of the line passing through (-2, 8) and perpendicular to y = 2x + 52 is 7. Answer: 7 (c).

Step-by-step explanation:

To find the y-intercept (b) of a line perpendicular to y = 2x + 52, we need to determine the equation of the new line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

The given line has a slope of 2, and the line perpendicular to it will have a negative reciprocal slope.

The negative reciprocal of 2 is -1/2, so the slope of the new line is -1/2.

Now we can use the coordinates of the point (-2, 8) to find the y-intercept. Substitute the values into the slope-intercept form and solve for b:

8 = (-1/2)(-2) + b

8 = 1 + b

b = 8 - 1

b = 7

Therefore, the y-intercept (b) of the line passing through (-2, 8) and perpendicular to y = 2x + 52 is 7.

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