192k views
2 votes
The height of a toy rocket during a 2.35-second flight is predicted by the function h(t)=−4t^3 + 6t^2 + 8t, where

h is the height in meters and t is the time in seconds. Find the height of the toy rocket 1.25 seconds into the flight.

A) 2.44 meters
B) 1.76 meters
C) 3.18 meters
D) 2.90 meters

1 Answer

3 votes

Final answer:

The height of the toy rocket 1.25 seconds into the flight, calculated using the provided function h(t)=−4t^3 + 6t^2 + 8t, is 11.5625 meters. The provided options do not match this result, suggesting a possible mistake in the question.

Step-by-step explanation:

To find the height of the toy rocket 1.25 seconds into the flight using the function h(t)=−4t^3 + 6t^2 + 8t, where h is the height in meters and t is the time in seconds, we need to plug the value of t = 1.25 seconds into the equation. Let's calculate it: h(1.25)=−4(1.25)^3 + 6(1.25)^2 + 8(1.25), h(1.25)=−4(1.953125) + 6(1.5625) + 8(1.25), h(1.25)=−7.8125 + 9.375 + 10, h(1.25)= 11.5625 meters. Thus, the height of the toy rocket 1.25 seconds into the flight is 11.5625 meters, which is not one of the options provided. The student might have made a mistake while transcribing the options or the function. However, based on the given function, this is the correct height.

User Chris Hinkle
by
8.2k points

Related questions

asked Sep 21, 2024 75.9k views
Amrish Prajapati asked Sep 21, 2024
by Amrish Prajapati
8.5k points
1 answer
0 votes
75.9k views
asked Sep 23, 2018 134k views
NLV asked Sep 23, 2018
by NLV
9.2k points
2 answers
4 votes
134k views
2 answers
5 votes
98.3k views
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.