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A gas occupies 9.5L at 50.5 kPa pressure. What is the volume at 200 mmHg at the same temperature?

a) 38.0L

b) 38.0×10³ L

c) 7.6×10³ L

d) 7.6L

User Baadshah
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1 Answer

2 votes

Answer:

The volume at 200 mmHg at the same temperature is 18.022 L. None of the options is true.

Explanation:

To solve this problem, we can use Boyle's Law, which states that the pressure of a given gas mass is inversely proportional to its volume at constant temperature.

Mathematically, this can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Given:

P1 = 50.5 kPa

V1 = 9.5 L

P2 = 200 mmHg

First, we need to convert the final pressure (P2) to the same unit as the initial pressure (P1), kPa.

1 mmHg = 0.133322 kPa

So, P2 = 200 mmHg * 0.133322 kPa/mmHg = 26.6644 kPa

Now, we can use Boyle's Law to find V2:

P1V1 = P2V2

V2 = (P1V1) / P2

V2 = (50.5 kPa * 9.5 L) / 26.6644 kPa

V2 ≈ 18.022 L

Thus, none of the options is true.

User Gordon Dickens
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