Question

A scientist is studying the growth of an exponius plant. The plant has an initial height of 10 cm and grows at a rate of 2% monthly.

Part A: Write an equation to model the growth of the plant.

A. H(t) = 10e^(0.02t)
B. H(t) = 10(1 + 0.02t)
C. H(t) = 10 + 0.02t
D. H(t) = 10t^0.02

Part B: Find the height of the plant after 6 months.

A. 10.2 cm
B. 12.0 cm
C. 11.2 cm
D. 20.0 cm

Answer 1

The equation to model the growth of the plant is H(t) = 10e^(0.02t). The height of the plant after 6 months is 11.2 cm.

Step-by-step explanation:

The equation to model the growth of the plant is H(t) = 10e^(0.02t).

To find the height of the plant after 6 months, we can substitute t = 6 into the equation:
H(6) = 10e^(0.02 * 6) = 11.2 cm.

Therefore, the height of the plant after 6 months is 11.2 cm.