Question

A stock solution has a concentration of 2.9 M. What volume of water) in mL would be needed in order to create 350 mL of a solution with a new concentration of 0.62 M?

Answer 1

To dilute a stock solution with a concentration of 2.9 M to create 350 mL of a solution with a new concentration of 0.62 M, you would need to mix the stock solution with a volume of water. The volume of water needed is approximately 0.86 mL.

Step-by-step explanation:

To dilute a stock solution with a concentration of 2.9 M to create 350 mL of a solution with a new concentration of 0.62 M, you would need to mix the stock solution with a certain volume of water. The formula to calculate the volume of water needed is:

(M1)(V1) = (M2)(V2)

Where:

• M1 is the initial concentration of the stock solution
• V1 is the volume of the stock solution
• M2 is the final desired concentration
• V2 is the final volume of the solution

In this case:

• M1 = 2.9 M
• V1 is the unknown volume of the stock solution
• M2 = 0.62 M
• V2 = 350 mL

By plugging in these values and solving for V1, you will find that the volume of water needed is approximately 0.86 mL.