Answer:
12.2 g
Step-by-step explanation:
Step 1: Write the balanced equation for the synthesis of SO₃ from S
S + 1.5 O₂ ⇒ SO₃
Step 2: Calculate the moles corresponding to 4.91 g of S
The molar mass of S is 32.07 g/mol.
4.91 g × 1 mol/32.07 g = 0.153 mol
Step 3: Calculate the theoretical yield, in moles, of SO₃ from 0.153 moles of S
The molar ratio of S to SO₃ is 1:1. The moles of SO₃ produced are 1/1 × 0.153 mol = 0.153 mol.
Step 4: Calculate the mass corresponding to 0.153 moles of SO₃
The molar mass of SO₃ is 80.06 g/mol.
0.153 mol × 80.06 g/mol = 12.2 g