Final answer:
By converting the volume of CH₃OH solution from mL to L and using the molarity, we find that there are 0.03272 moles of CH₃OH in 81.8 mL of 0.400 M CH₃OH.
Step-by-step explanation:
To determine how many moles of CH₃OH are in 81.8 mL of 0.400 M CH₃OH, we need to convert the volume from milliliters to liters and use the molarity as a conversion factor.
First, convert the volume from mL to L:
- 81.8 mL × (1 L/1000 mL) = 0.0818 L
Now, use the molarity to find the moles of CH₃OH:
- 0.0818 L × 0.400 moles/L = 0.03272 moles of CH₃OH
Molar concentration (also called molarity, amount concentration or substance concentration) is a measure of the concentration of a chemical species, in particular, of a solute in a solution, in terms of amount of substance per unit volume of solution. In chemistry, the most commonly used unit for molarity is the number of moles per liter, having the unit symbol mol/L or mol/dm3 in SI units.
A solution with a concentration of 1 mol/L is said to be 1 molar, commonly designated as 1 M or 1 M. Molarity is often depicted with square brackets around the substance of interest; for example, the molarity of the hydrogen ion is depicted as [H+].