Question

N the assembly shown points B and D are connected by double link members BD and points C and E are connected by a single link CE. Each of the three vertical links has an 10x 40-mm uniform rectangular cross section and each of the four pins has a 14-mm diameter. Member ABC has a 16 x 80-mm uniform rectangular cross section. For the loading shown, determine 1) The force in links BD (kN):

2) The force in link CE (kN)
3) The stress in link CE in (MPa)
4) The stress in link BD in (MPa):
5) The average shearing stress in the pin at C in (MPa).
6) The average shearing stress in the pin at B in (MPa).
7) The bearing stress at the pin C in (MPa).
8) The bearing stress at the pin B in (MPa):

Answer 1

The student is seeking calculations for forces and stresses in a mechanical assembly. However, the question lacks necessary information such as loading conditions and material properties, making it impossible to provide accurate answers without additional data on the assembly specifics.

Step-by-step explanation:

The student's question appears to be a complex engineering problem related to a specific type of mechanical assembly. Unfortunately, the description provided lacks crucial information necessary to calculate forces and stresses in the structure, such as the loading conditions, placement and orientation of the links, and the material properties involved. Without this data, it's impossible to provide accurate answers to the questions about the forces in links BD and CE, the stresses in these links, or the shear and bearing stresses in the pins at B and C.

To proceed with such an analysis, one would apply principles of static equilibrium to determine the forces in the links and pins. Then, by utilizing the cross-sectional areas and material properties of the links, the stresses in the respective components could be calculated. Shear stress is typically computed by dividing the shear force by the cross-sectional area experiencing the force, while bearing stress is determined by dividing the force by the projected area (force diameter times component thickness).