Final Answer:
Dissolve 180 g of glucose in .8 L of water, then bring the volume to 1L.
Step-by-step explanation:
To prepare a 1 M (molar) solution of glucose, you need to dissolve 180 grams of glucose in a volume less than 1 L and then bring the solution to a final volume of 1 L. This is because molarity is defined as moles of solute per liter of solution.
In this case, the molar mass of glucose is given as 180 g/mol, meaning 180 grams of glucose is equivalent to 1 mole. So, dissolving 180 g of glucose in a volume less than 1 L ensures a 1 M solution. Adding water to reach a final volume of 1 L then gives you the desired concentration.
The other options deviate from the correct procedure. Dissolving 180 g of glucose in 180 g of water would not result in a 1 M solution since the final volume would be less than 1 L. Similarly, dissolving 1 g of glucose in 0.1 L of water is insufficient to achieve a 1 M concentration.
Lastly, using 180 milligrams of glucose is not suitable for creating a 1 M solution, as the mass is much less than the required 180 grams. Therefore, the recommended procedure involves dissolving 180 g of glucose in a smaller volume and then diluting it to a final volume of 1 L.