Final answer:
In 1932, approximately 2.28% of children had very superior scores on the Stanford-Binet IQ test. If present-day children took the 1932 test, approximately 2.28% of them would also have very superior scores.
Step-by-step explanation:
In 1932, when the Stanford-Binet IQ test was first used, scores were adjusted to follow a normal distribution with a mean of 100 and a standard deviation of 15. To find the percentage of children with very superior scores (IQ > 130) in 1932, we need to calculate the area under the normal curve to the right of IQ = 130.
Using a z-score table or a calculator, we find that the z-score corresponding to IQ = 130 is (130 - 100) / 15 = 2. The area to the right of this z-score is approximately 0.0228, or 2.28%. Therefore, in 1932, approximately 2.28% of children had very superior scores.
If present-day American children took the 1932 test, we can assume that their scores would still follow the same normal distribution with a mean of 100 and a standard deviation of 15. To find the percentage of present-day children with very superior scores, we again calculate the area under the normal curve to the right of IQ = 130.
Using the same process as before, we find that the z-score is still 2. The area to the right of this z-score remains approximately 0.0228, or 2.28%. Therefore, if present-day children took the 1932 test, approximately 2.28% of them would have very superior scores.