Question

209 liters of water are poured into containers A, B, and C. B contains 50% more water than A, and C contains 50% more water than B. How many liters of water are in B?

A) 104.5 liters
B) 52.45 liters
C) 156.75 liters
D) 69.3 liters

Answer 1

To determine the amount of water in container B, we define the volume in A as x and calculate based on the given ratio. After setting up and solving the equation, it is found that B contains 66 liters of water, which is not listed in the provided options.

Step-by-step explanation:

The question asks us to find out how many liters of water are in container B when 209 liters of water are poured into three containers A, B, and C with specific proportional relationships. To solve this problem, let's define variable x as the amount of water in container A. Therefore, container B will contain x + 50% of x (which is 1.5x), and container C will contain 1.5 times the amount in B, which is 1.5 * 1.5x or 2.25x.

Since the total amount of water is 209 liters, we can write the equation as follows:

x + 1.5x + 2.25x = 209

Simplifying, we get:

4.75x = 209

Dividing both sides by 4.75, we find x:

x = 209 / 4.75 = 44 liters

Hence, container B, which contains 1.5 times the amount in A, will have:

1.5 * 44 = 66 liters

Therefore, the amount of water in container B is 66 liters, which is not one of the options provided.